Production and use of ultrasound
Section: Medical Physics | Syllabus: Cambridge A Level Physics (9702)
Production and Use of Ultrasound
Ultrasound consists of sound waves with frequencies above the human hearing range (typically 1 MHz to 20 MHz for medical applications). It is widely used for diagnostic imaging because it is non-invasive and does not involve ionising radiation.
The Piezoelectric Effect
Piezoelectric Effect A piezoelectric crystal changes shape when a potential difference (p.d.) is applied across it, and generates an electromotive force (e.m.f.) when its shape is changed by an external force. How Ultrasound is GeneratedAn alternating p.d. is applied across a piezoelectric crystal (e.g. quartz), causing it to expand and contract repeatedly at the frequency of the applied p.d. These rapid vibrations generate ultrasound waves in the surrounding medium.
How Ultrasound is DetectedWhen reflected ultrasound waves return and strike the piezoelectric crystal, they cause it to change shape. This generates a small e.m.f. across the crystal, which can be amplified and processed to form an image.
A piezoelectric transducer can therefore both generate and detect ultrasound pulses, making it ideal for medical imaging.
Figure: Piezoelectric TransducerCross-section of an ultrasound transducer showing:
- Piezoelectric crystal (e.g., quartz or PZT) at the centre
- Metal electrodes on front and back faces of crystal
- Backing material behind crystal to damp oscillations and produce short pulses
- Acoustic insulating layer
- Plastic/rubber membrane at front (contacts patient's skin)
- Coaxial cable connection to electrical supply
When an alternating p.d. is applied, the crystal vibrates, emitting ultrasound pulses. When returning echoes strike the crystal, they generate an e.m.f. that is detected.
Reflection at Tissue Boundaries
When ultrasound travels through the body, it reflects at boundaries between different tissues. The amount of reflection depends on the difference in specific acoustic impedance between the two media.
Specific Acoustic Impedance (Z) The specific acoustic impedance of a medium is defined as the product of its density and the speed of sound in that medium. Z = ρ cwhere ρ = density (kg m^-3) and c = speed of sound (m s^-1)
Unit of Z: kg m^-2 s^-1
| Material | Speed of sound / m s^-1 | Density / kg m^-3 | Z / × 10^6 kg m^-2 s^-1 |
|---|---|---|---|
| Air | 330 | 1.3 | 0.000429 |
| Fat | 1450 | 952 | 1.38 |
| Muscle | 1580 | 1080 | 1.71 |
| Skin | 1730 | 1150 | 1.99 |
| Bone | 3500 | 1850 | 6.48 |
Intensity Reflection Coefficient
When ultrasound is incident normally on a boundary between two media, some is reflected and some is transmitted. The proportion reflected depends on the difference in acoustic impedances.
Intensity Reflection Coefficient (α) The ratio of the reflected intensity to the incident intensity at a boundary between two media. α = (I_R/I_0) = ((Z_1 - Z_2)^2/(Z_1 + Z_2)^2)where I_R = reflected intensity, I_0 = incident intensity, Z_1 and Z_2 = acoustic impedances of the two media Key Points
- If Z_1 ≈ Z_2: very little reflection (most ultrasound is transmitted)
- If Z_1 and Z_2 are very different: strong reflection
- The transmitted intensity: I_T = I_0 - I_R
Air has a very low acoustic impedance compared to skin. At an air-skin boundary, almost all ultrasound would be reflected. A coupling gel is applied between the transducer and skin to eliminate air gaps. The gel has a similar acoustic impedance to skin, allowing ultrasound to enter the body efficiently.
Figure: Reflection at Tissue BoundariesDiagram showing an ultrasound pulse travelling through the body:
- Incident wave with intensity I_0 approaches boundary between Medium 1 (impedance Z_1) and Medium 2 (impedance Z_2)
- Part of the wave is reflected (intensity I_R) back towards transducer
- Part is transmitted (intensity I_T) into the second medium
- The proportion reflected depends on the difference between Z_1 and Z_2
If Z_1 ≈ Z_2: most energy transmitted, weak echo. If Z_1 and Z_2 very different: strong reflection, strong echo.
Attenuation of Ultrasound
As ultrasound travels through tissue, its intensity decreases due to absorption (energy converted to heat) and scattering. This reduction in intensity is called attenuation.
I = I_0 e^-μ xwhere I = intensity at depth x, I_0 = initial intensity, μ = linear attenuation coefficient (m^-1 or cm^-1), x = distance travelled
The attenuation coefficient μ depends on the tissue type and is approximately proportional to ultrasound frequency. Higher frequencies are attenuated more rapidly.
Types of Ultrasound Scans
| Scan Type | Description | Application |
|---|---|---|
| A-scan (Amplitude) | Displays echo amplitude vs time on an oscilloscope. Used to measure distances. | Ophthalmology (measuring eye dimensions) |
| B-scan (Brightness) | Echo strength controls brightness of pixels. Multiple scans build a 2D image. | Foetal imaging, abdominal scans |
A-scan (Amplitude scan):
- Oscilloscope display showing echo amplitude (y-axis) vs time (x-axis)
- Each peak represents a reflection from a tissue boundary
- Time between peaks indicates distance between boundaries (using d = ct/2)
- Peak height indicates strength of reflection (related to impedance mismatch)
B-scan (Brightness scan):
- Echo strength converted to brightness of pixels
- Transducer moved across body surface, taking multiple A-scans
- Combined scans build up a 2D cross-sectional image
- Bright areas indicate strong reflections, dark areas indicate weak reflections
- Non-invasive and painless
- No ionising radiation (safe for foetus)
- Real-time imaging possible
- Better at imaging soft tissue than X-rays
- Relatively inexpensive and portable
- Cannot image through bone or air (large impedance mismatch causes total reflection)
- Limited penetration depth at high frequencies
- Image resolution lower than CT or MRI
Worked Examples
Worked Example: Calculating Acoustic ImpedanceQuestion: The average density of the human brain is 1100 kg m^-3 and its specific acoustic impedance is 1.60 × 10^6 kg m^-2 s^-1. Calculate the speed of ultrasound through the brain.
SolutionUsing Z = ρ c, rearranging for c:
c = (Z/ρ) = 1.60 × 10^61100 = 1450 m s^-1
Worked Example: Intensity Reflection CoefficientQuestion: Calculate the intensity reflection coefficient for ultrasound incident normally on a fat-muscle boundary. (Use values from the table above.)
SolutionZ_fat = 1.38 × 10^6 kg m^-2 s^-1, Z_muscle = 1.71 × 10^6 kg m^-2 s^-1
α = ((1.38 - 1.71)^2/(1.38 + 1.71)^2) × 10^12 / 10^12 = ((-0.33)^2/(3.09)^2) = (0.1089/9.55) = 0.011
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