Energy transfers, work and efficiency

Section: Work, Energy and Power  |  Syllabus: Cambridge AS Level Physics (9702)

What is Energy?

Energy is a quantity that must be transferred in order to do work. It is a scalar quantity (no direction). The SI unit is the joule (J).

Forms of Energy

Energy is stored in objects and systems in various forms:

Energy FormDescription
Chemical PotentialStored in chemical bonds (fossil fuels, food, batteries).
Elastic PotentialStored in objects changed in shape reversibly (stretched springs).
Gravitational PotentialStored due to position in a gravitational field.
KineticStored in any moving object.
NuclearStored in the nucleus of atoms (released in fission/fusion).

Ways of Transferring Energy

ProcessExamples
ElectricallyElectric current transferring energy from a battery to a lamp.
By RadiationElectromagnetic waves (light, X-rays).
MechanicallyBy forces (pushing a car, sound waves).
By HeatingThermal energy transfer due to temperature difference.

What is Work?

Work is done when a force causes an object to move. It is the product of force and displacement in the direction of the force.

W = Fs

Where F is a constant force.

Base Units of the Joule

Since Work = Force × Distance (N × m) and Force = Mass × Acceleration (kg × m s^-2):

1 Joule = 1 N m = 1 kg m^2 s^-2.

Work Done by a Variable Force

If the force is not constant, we cannot simply use W=Fs. Instead, the work done is the area under the force-displacement graph.

Figure 5.1: Area under a Force-Displacement Graph

Show a graph with Force (y-axis) vs Displacement (x-axis). A curved line indicates a changing force. Shade the area under the curve to represent the total work done. Highlight a small strip of width Δ s and height F to show W ≈ Σ F Δ s.

Calculating Work Done with Angles

If the force acts at an angle θ to the direction of motion, only the component of force in the direction of motion does work.

W = Fs cos θ Figure 5.2: Resolving Force Components

Show a model tractor being pulled by a force F at an angle θ to the horizontal. Show the horizontal component F cos θ (doing work) and the vertical component F sin θ (doing no work against horizontal motion).

Worked Example: Pulling a Box (Figure 5.3)

Question: A box is pulled across level ground by a rope inclined at 20° above the horizontal. The constant force applied is 140 N. Calculate the work done in moving the box 5.0 m.

Answer

We use the component of force in the direction of displacement (F cos θ).

W = F s cos θ

W = 140 × 5.0 × cos 20^ = 660 J

Conservation of Energy

Principle of Conservation of Energy The total energy of a closed system is constant. Energy cannot be created or destroyed, only transferred or converted from one form to another. Closed Systems

A "closed system" is one where no energy enters or leaves. For example, a battery and lamp can be treated as a system, but if heat escapes to the surrounding air, the air must be included in the "closed system" to balance the energy equation.

Discovery of the Neutrino

The conservation of energy is fundamental. When scientists observed beta decay, energy seemed to disappear. Rather than abandon the principle, they predicted a new particle (the neutrino) was carrying away the missing energy. This was later confirmed.

Efficiency

Efficiency measures how much input energy is converted to useful output energy.

Efficiency = (Useful Energy Output/Total Energy Input)

(Multiply by 100 for percentage)

Sankey Diagrams

Sankey diagrams visualize energy transfers. The width of the arrow represents the amount of energy.

Figure 5.9: Sankey Diagram

Show an input arrow (Energy transferred by electricity, 9 J) splitting into two: a thin arrow going straight (Light, 0.8 J) and a thick arrow curving down (Thermal energy, 8.2 J). This visually demonstrates the low efficiency of a filament bulb.

Worked Example: Power Station Efficiency

Scenario: A power station has Total Input 610 MJ. It produces 150 MJ useful electrical energy and 270 MJ useful thermal energy. 190 MJ is wasted.

Answer

Total Useful Output = 150 + 270 = 420 MJ.

Efficiency = 420 / 610 = 0.69.

Percentage Efficiency = 69\%

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